本文實例講述了Python基于高斯消元法計算線性方程組。分享給大家供大家參考,具體如下:
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#!/usr/bin/env python # coding=utf-8 # 以上的信息隨自己的需要改動吧 def print_matrix( info, m ): # 輸出矩陣 i = 0 ; j = 0 ; l = len (m) print info for i in range ( 0 , len ( m ) ): for j in range ( 0 , len ( m[i] ) ): if ( j = = l ): print ' |' , print '%6.4f' % m[i][j], print print def swap( a, b ): t = a; a = b; b = t def solve( ma, b, n ): global m; m = ma # 這里主要是方便最后矩陣的顯示 global s; i = 0 ; j = 0 ; row_pos = 0 ; col_pos = 0 ; ik = 0 ; jk = 0 mik = 0.0 ; temp = 0.0 n = len ( m ) # row_pos 變量標記行循環(huán), col_pos 變量標記列循環(huán) print_matrix( "一開始 de 矩陣" , m ) while ( ( row_pos < n ) and ( col_pos < n ) ): print "位置:row_pos = %d, col_pos = %d" % (row_pos, col_pos) # 選主元 mik = - 1 for i in range ( row_pos, n ): if ( abs ( m[i][col_pos] ) > mik ): mik = abs ( m[i][col_pos] ) ik = i if ( mik = = 0.0 ): col_pos = col_pos + 1 continue print_matrix( "選主元" , m ) # 交換兩行 if ( ik ! = row_pos ): for j in range ( col_pos, n ): swap( m[row_pos][j], m[ik][j] ) swap( m[row_pos][n], m[ik][n] ); # 區(qū)域之外? print_matrix( "交換兩行" , m ) try : # 消元 m[row_pos][n] / = m[row_pos][col_pos] except ZeroDivisionError: # 除零異常 一般在無解或無窮多解的情況下出現(xiàn)…… return 0 ; j = n - 1 while ( j > = col_pos ): m[row_pos][j] / = m[row_pos][col_pos] j = j - 1 for i in range ( 0 , n ): if ( i = = row_pos ): continue m[i][n] - = m[row_pos][n] * m[i][col_pos] j = n - 1 while ( j > = col_pos ): m[i][j] - = m[row_pos][j] * m[i][col_pos] j = j - 1 print_matrix( "消元" , m ) row_pos = row_pos + 1 ; col_pos = col_pos + 1 for i in range ( row_pos, n ): if ( abs ( m[i][n] ) = = 0.0 ): return 0 return 1 if __name__ = = '__main__' : matrix = [[ 2.0 , 0.0 , - 2.0 , 0.0 ], [ 0.0 , 2.0 , - 1.0 , 0.0 ], [ 0.0 , 1.0 , 0.0 , 10.0 ]] i = 0 ; j = 0 ; n = 0 # 輸出方程組 print_matrix( "一開始的矩陣" , matrix ) # 求解方程組, 并輸出方程組的可解信息 ret = solve( matrix, 0 , 0 ) if ( ret! = 0 ): print "方程組有解\n" else : print "方 程組無唯一解或無解\n" # 輸出方程組及其解 print_matrix( "方程組及其解" , matrix ) for i in range ( 0 , len ( m ) ): print "x[%d] = %6.4f" % (i, m[i][ len ( m )]) |
運行結(jié)果:
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一開始的矩陣 2.0000 0.0000 - 2.0000 | 0.0000 0.0000 2.0000 - 1.0000 | 0.0000 0.0000 1.0000 0.0000 | 10.0000 一開始 de 矩陣 2.0000 0.0000 - 2.0000 | 0.0000 0.0000 2.0000 - 1.0000 | 0.0000 0.0000 1.0000 0.0000 | 10.0000 位置:row_pos = 0 , col_pos = 0 選主元 2.0000 0.0000 - 2.0000 | 0.0000 0.0000 2.0000 - 1.0000 | 0.0000 0.0000 1.0000 0.0000 | 10.0000 交換兩行 2.0000 0.0000 - 2.0000 | 0.0000 0.0000 2.0000 - 1.0000 | 0.0000 0.0000 1.0000 0.0000 | 10.0000 消元 1.0000 0.0000 - 1.0000 | 0.0000 0.0000 2.0000 - 1.0000 | 0.0000 0.0000 1.0000 0.0000 | 10.0000 位置:row_pos = 1 , col_pos = 1 選主元 1.0000 0.0000 - 1.0000 | 0.0000 0.0000 2.0000 - 1.0000 | 0.0000 0.0000 1.0000 0.0000 | 10.0000 交換兩行 1.0000 0.0000 - 1.0000 | 0.0000 0.0000 2.0000 - 1.0000 | 0.0000 0.0000 1.0000 0.0000 | 10.0000 消元 1.0000 0.0000 - 1.0000 | 0.0000 0.0000 1.0000 - 0.5000 | 0.0000 0.0000 0.0000 0.5000 | 10.0000 位置:row_pos = 2 , col_pos = 2 選主元 1.0000 0.0000 - 1.0000 | 0.0000 0.0000 1.0000 - 0.5000 | 0.0000 0.0000 0.0000 0.5000 | 10.0000 交換兩行 1.0000 0.0000 - 1.0000 | 0.0000 0.0000 1.0000 - 0.5000 | 0.0000 0.0000 0.0000 0.5000 | 10.0000 消元 1.0000 0.0000 0.0000 | 20.0000 0.0000 1.0000 0.0000 | 10.0000 0.0000 0.0000 1.0000 | 20.0000 方程組有解 方程組及其解 1.0000 0.0000 0.0000 | 20.0000 0.0000 1.0000 0.0000 | 10.0000 0.0000 0.0000 1.0000 | 20.0000 x[ 0 ] = 20.0000 x[ 1 ] = 10.0000 x[ 2 ] = 20.0000 |
希望本文所述對大家Python程序設(shè)計有所幫助。
原文鏈接:http://blog.csdn.net/zuyuanzhu/article/details/21184723