本文實例講述了java使用Hashtable過濾數組中重復值的方法。分享給大家供大家參考，具體如下：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
|
package org.eline.core.web.support;import java.util.Hashtable;/***************************** * * @author zdw * */public class ObjectFilter{ public static void main(String[] args) { // String 測試 String arr[] = { "13111", "13112", "13111" }; ObjectFilter sf = new ObjectFilter(); Object results[] = sf.filter(arr); System.out.println(results.length); for (int i = 0; i < results.length; ++i) { System.out.println(results[i]); } // 整形測試 Integer arr2[] = { 1, 3, 5, 7, 1, 2, 4, 5 }; Object results2[] = sf.filter(arr2); for (int i = 0; i < results2.length; ++i) { System.out.println(results2[i]); } } /************************* * 過濾的方法 * * @param arr * 要過濾的數組 * @return */ public Object[] filter(Object arr[]) { Hashtable<Object, Object> hashtable = new Hashtable<Object, Object>(); for (int i = 0; i < arr.length; ++i) { hashtable.put(arr[i], arr[i]); } Object results[] = null; results = hashtable.values().toArray(); return results; }} |
希望本文所述對大家java程序設計有所幫助。
