看了一眼自關聯，沒搞懂，試了一下也沒成功。
over方式一下結果就出來了，好用。
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/*需求：累計求和六種算法效率比較作者：felix日期：2020-06-23*/--第一步，準備測試數據--IF OBJECT_ID(N'dbo.t') IS NOT NULL-- DROP TABLE dbo.t;--GO--CREATE TABLE dbo.t--(-- i BIGINT IDENTITY(1, 1) PRIMARY KEY,-- d MONEY--);--INSERT t-- d--)--SELECT TOP 31465-- ROUND(10000 * RAND(CHECKSUM(NEWID())), 2)--FROM sys.all_objects AS a-- CROSS JOIN sys.all_objects;----第二步，創建記錄時間的表格--IF OBJECT_ID(N'dbo.record_time') IS NOT NULL-- DROP TABLE dbo.record_time;--CREATE TABLE dbo.record_time-- i INT IDENTITY PRIMARY KEY,-- 算法 NVARCHAR(10),-- bt DATETIME2,--開始時間-- et DATETIME2,--結束時間-- idiff AS DATEDIFF(ms, bt, et)--所用的毫秒數--第一種方法，自連接法，sql server 2008以上版本測試通過，157255661.40SET STATISTICS TIME OFF;SET STATISTICS IO OFF;GODECLARE @bt DATETIME2 = GETDATE();SELECT a.i, a.d, SUM(b.d) AS total_sumFROM dbo.t AS a INNER JOIN dbo.t AS b ON b.i <= a.iGROUP BY a.i, a.d;DECLARE @et DATETIME2 = GETDATE();INSERT INTO dbo.record_time( 算法, bt, et)VALUES('自連接', @bt, @et);--ORDER BY a.i;;--第二種方法，遞歸，sql server 2008以上版本測試通過，157255661.40WITH cte_total_sumAS (SELECT i, d, d AS total_sum FROM dbo.t WHERE i = 1 UNION ALL SELECT s.i, s.d, p.total_sum + s.d AS total_sum FROM dbo.t AS s INNER JOIN cte_total_sum AS p ON s.i - 1 = p.i)SELECT *FROM cte_total_sumOPTION (MAXRECURSION 0);('遞歸', @bt, @et);--第三種方法，over 子句，sql server 2012測試通過，sql server 2008不支持，157255661.40SELECT i, d, SUM(d) OVER (ORDER BY i) AS total_sumFROM dbo.t;('over子句', @bt, @et);--第四種，相關子查詢，sql server 2008以上版本測試通過，156625045.22SELECT outquery.i, outquery.d, ( SELECT SUM(innerq.d) FROM dbo.t AS innerq WHERE innerq.i <= outquery.i ) AS ct --內部查詢FROM dbo.t AS outquery;('相關子查詢', @bt, @et);--ORDER BY outquery.i; --外部查詢--游標方法，有兩種方法可以實現，一種是臨時表更新，一種是變量疊加更新，157255661.40--先增加一個存儲累計和的列--第5種，游標_臨時表更新--ALTER TABLE dbo.t ADD total_d MONEY DEFAULT (0);--只運行一次DECLARE @t TABLE --定義表變量，存儲累計求和臨時結果 i INT PRIMARY KEY IDENTITY, d MONEY, total_d MONEY);DECLARE @i INT = 0, @d MONEY = 0, @total_d MONEY = 0;DECLARE c1 CURSOR FOR SELECT i, d FROM dbo.t ORDER BY i;OPEN c1;FETCH c1INTO @i, @d;WHILE @@FETCH_STATUS = 0BEGIN SET @total_d += @d; INSERT INTO @t ( d, total_d ) VALUES (@d, @total_d); FETCH c1 INTO @i, @d;END;CLOSE c1;DEALLOCATE c1;UPDATE dbo.tSET total_d = b.total_d INNER JOIN @t AS b ON a.i = b.i;('游標_臨時表更新', @bt, @et);--第6種，游標_變量疊加更新DECLARE c1 CURSOR FOR SELECT i, d FROM dbo.t; --ORDER BY i; UPDATE dbo.t SET total_d = @total_d WHERE i = @i;('游標_變量疊加更新', @bt, @et);--執行時間 over子句<游標臨時表更新<游標變量疊加更新<自連接<相關子查詢<遞歸查詢 |
補充：下面看下SQL server 累加求和
SQL server 累加求和
1.
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SELECT SalesOrderID, ProductID, OrderQty ,SUM(OrderQty) OVER(PARTITION BY SalesOrderID) AS Total ,AVG(OrderQty) OVER(PARTITION BY SalesOrderID) AS "Avg" ,COUNT(OrderQty) OVER(PARTITION BY SalesOrderID) AS "Count" ,MIN(OrderQty) OVER(PARTITION BY SalesOrderID) AS "Min" ,MAX(OrderQty) OVER(PARTITION BY SalesOrderID) AS "Max"FROM Sales.SalesOrderDetail WHERE SalesOrderID IN(43659,43664); |
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select SchSno,convert(varchar(10),a.Dates,120) Dates,sum(Amt_avail) over(partition by SchSno order by convert(varchar(10),a.Dates,120)) as PeriodPreAmtfrom jr_creditUserAcct a |
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原文鏈接：https://www.cnblogs.com/luna-hehe/p/15935342.html
